Hydraulic Radius of a Triangular Channel

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

hydraulic radius of a triangleHydraulic radius, abbreviated as \(r_h\), is the cross section area of water in a pipe or channel divided by the wetting perimeter.

Hydraulic Radius of a Triangular Channel formula

(Eq. 1)  \(\large{ r_h =  \frac  {  A }  { P }   }\)         

(Eq. 2)  \(\large{ r_h =  \frac  {  zh^2 }  { 2h  \sqrt  {1  +  z^2 } }   }\)

Where:

\(\large{ r_h }\) = hydraulic radius

\(\large{ b }\) = bottom width of fluid

\(\large{ A }\) = cross section flow area

\(\large{ h }\) = depth of fluid

\(\large{ w }\) = top width of fluid

\(\large{ P }\) = wetted perimeter

\(\large{ z }\) = width of channel slope

Solve for:

\(\large{ A =  zh^2  }\)

\(\large{ P = 2h  \sqrt  {1  +  z^2 }  }\)

 

Tags: Equations for Hydraulic