Gas Pressure Loss through Piping

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

Gas Pressure Loss through Piping formula

\(\large{ p_l = \frac { \mu \;  l \;  {v_g}^2 \; \rho } { 2 \; d }   }\)   

Where:

 Units English Metric
\(\large{ p_l }\) = gas pressure loss \(\large{\frac{lbf}{in^2}}\) \(\large{Pa}\)
\(\large{ \rho }\)  (Greek symbol rho) = density of gas \(\large{\frac{lbm}{ft^3}}\) \(\large{\frac{kg}{m^3}}\)
\(\large{ v_g }\) = velocity of gas \(\large{\frac{ft}{sec}}\) \(\large{\frac{m}{s}}\)
\(\large{ \mu }\)  (Greek symbol mu) = friction coefficient \(\large{dimensionless}\)
\(\large{ d }\) = inside diameter of pipe \(\large{in}\) \(\large{mm}\)
\(\large{ l }\) = pipe length \(\large{ft}\) \(\large{m}\)

 

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Tags: Pressure Equations Pipe Sizing Equations Gas Equations