# Maximum Height of a Projectile

Written by Jerry Ratzlaff on . Posted in Classical Mechanics

## Maximum Height of a Projectile formulas

 $$\large{ h_{max} = \frac{ v_0 \; sin^2 \; \theta }{ 2 \; g } }$$

### Where:

$$\large{ h_{max} }$$ = maximum height

$$\large{ g }$$ = gravitational acceleration

$$\large{ v_0 }$$ = launch velocity

$$\large{ \theta }$$ = vertical angle