Mechanical Efficiency
Mechanical Efficiency Formulas
\(\large{ \eta_m = \frac{ PSI \; 100 }{ TT } }\) | (motor (pressure differential PSI) ) |
\(\large{ \eta_m = \frac{ PSI \; 100 }{ TP } }\) | (pump (gauge pressure PSI) ) |
Where:
\(\large{ \eta_m }\) (Greek symbol eta) = mechanical efficiency
\(\large{ CIR }\) = cubic inch per revolution
\(\large{ PSI }\) = gauge pressure in pounds per square inch
\(\large{ PSI }\) = pressure differential across motor in pounds per square inch
\(\large{ TP }\) = theoretical pressure
\(\large{ TT }\) = theoretical torque
\(\large{ \tau }\) (Greek symbol tau) = torque
Solve for:
\(\large{ TT = \frac{ CIR \; PSI }{ 6.28 } }\) | (motor) |
\(\large{ TP = \frac{ \tau \; 6.28 }{ CIR } }\) | (pump) |
Tags: Equations for Efficiency