# Hydraulic Radius of a Triangular Channel

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

Hydraulic radius, abbreviated as $$r_h$$, is the area cross-section of water in a pipe or channel divided by the wetting perimeter.

## Hydraulic Radius of a Triangular Channel formulas

 $$\large{ r_h = \frac { A_c } { P_w } }$$ $$\large{ r_h = \frac { z\;h^2 } { 2\;h \; \sqrt {1 \;+\; z^2 } } }$$

### Where:

 Units English Metric $$\large{ r_h }$$ = hydraulic radius $$\large{ft}$$ $$\large{m}$$ $$\large{ A_c }$$ = area cross-section of flow $$\large{ft^2}$$ $$\large{m^2}$$ $$\large{ b }$$ = bottom width of fluid $$\large{ft}$$ $$\large{m}$$ $$\large{ h }$$ = depth of fluid $$\large{ft}$$ $$\large{m}$$ $$\large{ w }$$ = top width of fluid $$\large{ft}$$ $$\large{m}$$ $$\large{ P_w }$$ = wetting perimeter $$\large{ft}$$ $$\large{m}$$ $$\large{ z }$$ = width of channel slope $$\large{ft}$$ $$\large{m}$$

Tags: Hydraulic Equations