Hydraulic Radius of a Triangular Channel

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

hydraulic radius of a triangleHydraulic radius, abbreviated as \(r_h\), is the area cross-section of water in a pipe or channel divided by the wetting perimeter.

 

Hydraulic Radius of a Triangular Channel formulas

\(\large{ r_h =  \frac  {  A_c }  { P_w }   }\)    
\(\large{ r_h =  \frac  {  z\;h^2 }  { 2\;h \; \sqrt  {1  \;+\;  z^2 } }   }\)   

Where:

 Units English Metric
\(\large{ r_h }\) = hydraulic radius \(\large{ft}\) \(\large{m}\)
\(\large{ A_c }\) = area cross-section of flow \(\large{ft^2}\) \(\large{m^2}\)
\(\large{ b }\) = bottom width of fluid \(\large{ft}\) \(\large{m}\)
\(\large{ h }\) = depth of fluid \(\large{ft}\) \(\large{m}\)
\(\large{ w }\) = top width of fluid \(\large{ft}\) \(\large{m}\)
\(\large{ P_w }\) = wetting perimeter \(\large{ft}\) \(\large{m}\)
\(\large{ z }\) = width of channel slope \(\large{ft}\) \(\large{m}\)

 

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Tags: Hydraulic Equations