Two Span Continuous Beam - Equal Spans, Two Equal Concentrated Loads Symmetrically Placed
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Two Span Continuous Beam - Equal Spans, Two Equal Concentrated Loads Symmetrically Placed formulas
| \(\large{ R_1 = V_1 = R_3 = V_3 = \frac{5\;P}{16} }\) | |
| \(\large{ R_2 = 2V_2 = \frac{11\;P}{8} }\) | |
| \(\large{ V_2 = P - R_1 = \frac{11\;P}{16} }\) | |
| \(\large{ V_{max} = V_2 }\) | |
| \(\large{ M_1 = \frac{3\;P\;L}{16} }\) | |
| \(\large{ M_2 = \frac{5\;P\;L}{32} }\) | |
| \(\large{ M_x \; \left( x < \frac{L}{2} \right) = R_1\; x }\) |
Where:
\(\large{ I }\) = moment of inertia
\(\large{ L }\) = span length of the bending member
\(\large{ M }\) = maximum bending moment
\(\large{ P }\) = total concentrated load
\(\large{ R }\) = reaction load at bearing point
\(\large{ V }\) = shear force
\(\large{ w }\) = load per unit length
\(\large{ W }\) = total load from a uniform distribution
\(\large{ x }\) = horizontal distance from reaction to point on beam
\(\large{ \lambda }\) (Greek symbol lambda) = modulus of elasticity
\(\large{ \Delta }\) = deflection or deformation