# Compression

on . Posted in Classical Mechanics

Compression, abbreviated as K, is the force (pressure) acting on a material.

## Compression formulas

$$\large{ \Delta d = d_i - d_f }$$

$$\large{ \Delta d = \epsilon_{di} \; d_i }$$

$$\large{ \Delta d = \frac{ \mu \; \sigma }{ \lambda } \; d_i }$$

$$\large{ \Delta d = \frac{ \mu \; p }{ \lambda \; A } \; d_i }$$

$$\large{ \Delta l = l_f - l_i }$$

$$\large{ \Delta l = \lambda \; l_i }$$

$$\large{ \Delta l = \frac{ \sigma }{ \lambda } \; l_i }$$

$$\large{ \Delta l = \frac{ p }{ \lambda \; A } \; l_i }$$

Symbol English Metric
$$\large{ \Delta d }$$ = depth change $$\large{ in }$$ $$\large{ mm }$$
$$\large{ \Delta l }$$ = length change $$\large{ in }$$ $$\large{ mm }$$
$$\large{ A }$$ = area $$\large{ in^2 }$$ $$\large{ mm^2 }$$
$$\large{ d_f }$$ = final depth $$\large{ in }$$ $$\large{ mm }$$
$$\large{ d_i }$$ = initial depth $$\large{ in }$$ $$\large{ mm }$$
$$\large{ \lambda }$$  (Greek symbol lambda) = elastic modulus $$\large{\frac{lbf}{in^2}}$$ $$\large{Pa}$$
$$\large{ l_f }$$ = final length $$\large{ in }$$ $$\large{ mm }$$
$$\large{ l_i }$$ = initial length $$\large{ in }$$ $$\large{ mm }$$
$$\large{ \mu }$$  (Greek symbol mu) = Poisson's Ratio $$\large{ dimensionless }$$
$$\large{ p }$$ = pressure under consideration $$\large{\frac{lbf}{in^2}}$$ $$\large{Pa}$$
$$\large{ \epsilon }$$  (Greek symbol epsilon) = strain $$\large{\frac{in}{in}}$$ $$\large{\frac{mm}{mm}}$$