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Two Member Frame - Fixed/Fixed Top Uniformly Distributed Load

Diagram Symbols

Bending moment diagram (BMD)  -  Used to determine the bending moment at a given point of a structural element.  The diagram can help determine the type, size, and material of a member in a structure so that a given set of loads can be supported without structural failure.
Free body diagram (FBD)  -  Used to visualize the applied forces, moments, and resulting reactions on a structure in a given condition.
Shear force diagram (SFD)  -  Used to determine the shear force at a given point of a structural element.  The diagram can help determine the type, size, and material of a member in a structure so that a given set of loads can be supported without structural failure.
Uniformly distributed load (UDL)  -  A load that is distributed evenly across the entire length of the support area.

 

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Two Member Frame - Fixed/Fixed Top Uniformly Distributed Load

\( e  \;=\;    \dfrac{ h }{ L }  \) 

\( \beta \;=\;    \dfrac{ I_h }{ I_v }  \) 

\( R_A  \;=\;    \dfrac{w \cdot L }{ 8 }   \cdot    \dfrac{ 3 \cdot \beta \cdot e + 4 }{ \beta \cdot e + 1 }  \) 

\( R_C  \;=\;    \dfrac{ w \cdot L }{ 8 }   \cdot    \dfrac{ 5 \cdot \beta \cdot e + 4 }{ \beta \cdot e + 1 }  \)

\( H_A =  H_C  \;=\;    \dfrac{ w \cdot L^2 }{ 8 \cdot h \cdot \left( \beta \cdot e + 1 \right)  }   \)

\( M_A \;=\;    \dfrac{ w \cdot L^2 }{ 24 \cdot \left( \beta \cdot e + 1 \right)  }   \)

\( M_B \;=\;     \dfrac{ w \cdot L^2 }{ 12 \cdot \left( \beta \cdot e + 1 \right)  }   \)

\( M_C  \;=\;    \dfrac{ w\cdot L^2 }{ 24 }   \cdot     \dfrac{ 3 \cdot \beta \cdot e + 2 }{ \beta \cdot e + 1 }   \)

Symbol English Metric
\( R \) = vertical reaction load at bearing point \(lbf\) \(N\)
\( H \) = horizontal reaction load at bearing point \(lbf\) \(N\)
\( M \) = maximum bending moment \(lbf-in\) \(N-mm\)
 \( h \) = height of frame \(in\) \(mm\)
\( L \) = span length under consideration \(in\) \(mm\)
\( I_h \) = horizontal member second moment of area (moment of inertia) \(in^4\) \(mm^4\)
\( I_v \) = vertical member second moment of area (moment of inertia) \(in^4\) \(mm^4\)
\( P \) = total concentrated load \(lbf\) \(N\)
\( A, B, C, D, E \) = point of intrest on frame \(dimensionless\) \(dimensionless\)

 

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