# Condensate Load from Heating Air

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

## Condensate Load from Heating Air formula

 $$\large{ m_c = \frac { 60 \; c_a \; \gamma_a \; Q_a \; \left( T_o \;-\; T_i \right) } { L_s } }$$

### Where:

 Units English Metric $$\large{ m_c }$$ = condensate load $$lbm$$ $$kg$$ $$\large{ Q_a }$$ = flow rate of air $$\large{\frac{ft^3}{sec}}$$ $$\large{\frac{m^3}{s}}$$ $$\large{ L_s }$$ = latent heat of steam $$\large{\frac{Btu}{lbm}}$$ $$\large{\frac{kJ}{kg}}$$ $$\large{ c_a }$$ = specific heat of air $$\large{\frac{Btu}{lbm-F}}$$ $$\large{\frac{kJ}{kg-K}}$$ $$\large{ \gamma_a }$$  (Greek symbol gamma) = specific weight of air $$\large{\frac{lbf}{ft^3}}$$ $$\large{\frac{N}{m^3}}$$ $$\large{ T_i }$$ = inlet temperature of air $$\large{F}$$ $$\large{K}$$ $$\large{ T_o }$$ = outlet temperature of air $$\large{F}$$ $$\large{K}$$