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Simple Beam - Load Increasing Uniformly to Center

Diagram Symbols

Bending moment diagram (BMD)  -  Used to determine the bending moment at a given point of a structural element.  The diagram can help determine the type, size, and material of a member in a structure so that a given set of loads can be supported without structural failure.
Free body diagram (FBD)  -  Used to visualize the applied forces, moments, and resulting reactions on a structure in a given condition.
Shear force diagram (SFD)  -  Used to determine the shear force at a given point of a structural element.  The diagram can help determine the type, size, and material of a member in a structure so that a given set of loads can be supported without structural failure.
Uniformly distributed load (UDL)  -  A load that is distributed evenly across the entire length of the support area.

 

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Simple Beam - Load Increasing Uniformly to Center formulas

\( R = V_{max} \;=\;  \dfrac{ W }{ 2 }\)

\( V_x  \;  [ \; x < (L\;/\;2) \;]  \;=\;  \dfrac{ W }{ 2 \cdot L^2 }  \cdot ( L^2 - 4 \cdot x^2 ) \)

\( M_{max}  \; (at \;center) \;=\;  \dfrac{ W \cdot L }{ 6  }\)

\( M_x \; [\;  x < (L\;/\;2) \;]  \;=\;  W \cdot x \cdot  \left(\dfrac{1}{2}  - \dfrac{ 2 \cdot x^2 }{ 3 \cdot L^2 }  \right)\)

\( \Delta_{max} \; (at \;center) \;=\;  \dfrac{ W \cdot L^3 }{ 60 \cdot \lambda \cdot I }\)

\( \Delta_x \; [\;  x < (L\;/\;2) \;]  \;=\;   \dfrac{ W \cdot x }{ 480 \cdot \lambda \cdot I \cdot L^2 }  \cdot  (  5 \cdot L^2 - 4 \cdot x^2 )^2   \)

Symbol English Metric
\( R \) = reaction load at bearing point \(lbf\) \(N\)
\( V \) = maximum shear force \(lbf\) \(N\)
\( M \) = maximum bending moment \(lbf-in\) \(N-mm\)
\( \Delta \) = deflection or deformation \(in\) \(mm\)
\( W \) = total load or \( w\;L\;/\;2 \) \(lbf\) \(N\)
\( w \) = highest load per unit length of UIL \(lbf\;/\;in\) \(N\;/\;m\)
\( L \) = span length of the bending member \(in\) \(mm\)
\( x \) = horizontal distance from reaction to point on beam \(in\) \(mm\)
\( \lambda  \)   (Greek symbol lambda) = modulus of elasticity \(lbf\;/\;in^2\) \(Pa\)
\( I \) = second moment of area (moment of inertia) \(in^4\) \(mm^4\)

 

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